Question
If \sqrt[3]{8x+6}=-3 , what is the value of x ?
If \sqrt[3]{8x+6}=-3 , what is the value of x ?
Cube both sides to get rid of cube-root symbol
\big( \sqrt[3]{8x+6}\big) ^3 = (-3)^3
8x+6 = -27
Subtract 6 from both sides
8x = -33
Divide both sides by 8
x = - \dfrac{33}{8}