If x = \sqrt[3]{25}+\sqrt[3]{20}+\sqrt[3]{16} ,
find the value of x -\dfrac{1}{x^2}
Find the value of (\sqrt[3]{\sqrt{5}+2 }+\sqrt[3]{\sqrt{5}-2 } )^{2014}
Find cube root of \sqrt[3]{55+63\sqrt{2}}
Solve the cube root equation
\sqrt[3]{x+302} - \sqrt[3]{x-302} = 4
\sqrt[3]{x+224} - \sqrt[3]{x-224} = 4
\sqrt[3]{x+158} - \sqrt[3]{x-158} = 4
\sqrt[3]{x+104} - \sqrt[3]{x-104} = 4
\sqrt[3]{x+62} - \sqrt[3]{x-62} = 4
\sqrt[3]{x+301} - \sqrt[3]{x-301} = 2
\sqrt[3]{x+244} - \sqrt[3]{x-244} = 2
\sqrt[3]{x+193} - \sqrt[3]{x-193} = 2
\sqrt[3]{x+148} - \sqrt[3]{x-148} = 2
\sqrt[3]{x+109} - \sqrt[3]{x-109} = 2
\sqrt[3]{x+76} - \sqrt[3]{x-76} = 2
\sqrt[3]{x+49} - \sqrt[3]{x-49} = 2
