Multiple Choice Question (MCQ)

Points A(\sqrt{2},4 ) , B(6,-\sqrt{3} ) , and C are collinear. If B is the midpoint of line segment AC , approximately what are the (x,y) coordinates of point C ?

  1. ×

    (3.71,1.13)

  2. ×

    (3.71,5.73)

  3. ×

    (7.41,-7.46)

  4. (10.59, -7.46)

  5. ×

    (10.59, 5.73)

Collected in the board: Coordinate geometry

Steven Zheng posted 2 months ago


Answer

  1. B is the midpoint of line segment AC

    \dfrac{\sqrt{2}+x }{2}=6

    x= 12-\sqrt{2}\approx 10.59

    and,


    \dfrac{4+y}{2}=-\sqrt{3}

    y = -2\sqrt{3} -4 \approx -7.46

Steven Zheng posted 2 months ago

Scroll to Top