Question


Answer

a^{1/2}+a^{-1/2}=3

Square the both sides,

a+a^{-1}+2=9

a+a^{-1}=7
(1)

Square both sides of above equation,


a^2+a^{-2}=47
(2)

Plug in (1) and (2), we get


\dfrac{a^2+a^{-2}+1}{a+a^{-1}-1}=\dfrac{47+1}{7-1} =8

Steven Zheng posted 3 months ago

Scroll to Top