Multiple Choice Question (MCQ)
If 2y^2+x4 = 0 , and \dfrac{x}{2}=y^2 , then x =

×
1

✓
2

×
3

×
4

×
5
If 2y^2+x4 = 0 , and \dfrac{x}{2}=y^2 , then x =
1
2
3
4
5
Since two equations are given with two variables, the solution set can be determined.
For variable y, it appears in the form of its square in both equations. So the y^2 could be taken a variable of one degree in the course of solution.
Since \dfrac{x}{2}=y^2 , that is,
y^2 = \dfrac{x}{2}
Plug in the equation 2y^2+x4=0
we get,
2\cdotp \dfrac{x}{2}+x=4
2x = 4
Dividing both sides by 2 gives final result
\therefore x = 2
Therefore,
B is the choice.