Multiple Choice Question (MCQ)

If 2y^2+x-4 = 0 , and \dfrac{x}{2}=y^2 , then x =

  1. ×

    1

  2. 2

  3. ×

    3

  4. ×

    4

  5. ×

    5

Collected in the board: Algebraic equation

Steven Zheng posted 3 years ago

Answer

  1. Since two equations are given with two variables, the solution set can be determined.

    For variable y, it appears in the form of its square in both equations. So the y^2 could be taken a variable of one degree in the course of solution.

    Since \dfrac{x}{2}=y^2 , that is,

    y^2 = \dfrac{x}{2}

    Plug in the equation 2y^2+x-4=0

    we get,

    2\cdotp \dfrac{x}{2}+x=4

    2x = 4

    Dividing both sides by 2 gives final result

    \therefore x = 2

    Therefore,

    B is the choice.

Steven Zheng posted 2 years ago

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