If $$ 2y^2+x-4 = 0 $$ , and $$ \dfrac{x}{2}=y^2 $$ , then $$ x = $$

Question

If $$ 2y^2+x-4 = 0 $$ , and $$ \dfrac{x}{2}=y^2 $$ , then $$ x =  $$

Uniteasy Admin · Accepted Answer

Since two equations are given with two variables, the solution set can be determined.
For variable $$y$$, it appears in the form of its square in both equations. So the $$y^2$$ could be taken a variable of one degree in the course of solution.
Since $$\dfrac{x}{2}=y^2  $$, that is,
$$y^2 = \dfrac{x}{2}$$
Plug in the equation $$2y^2+x-4=0$$ 
we get,
$$2\cdotp  \dfrac{x}{2}+x=4$$
$$2x = 4$$
Dividing both sides by 2 gives final result
$$	herefore  x = 2 $$ 
Therefore,
B is the choice.

Multiple Choice Question (MCQ)

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