Multiple Choice Question (MCQ)
In the figure, the area of rectangle CDEF is twice the area of rectangle ABCF . If CD=2x+2 , what is the length of AE , in terms of x ?

×
2x=2

×
2x+4

×
3x+1

×
3x+2

✓
3x+3
In the figure, the area of rectangle CDEF is twice the area of rectangle ABCF . If CD=2x+2 , what is the length of AE , in terms of x ?
2x=2
2x+4
3x+1
3x+2
3x+3
Since the area of rectangle CDEF is twice the area of rectangle ABCF and the two triangles share sides in the same length,
CD = 2BC
BC = \dfrac{1}{2}CD
=\dfrac{1}{2}(2x+2)
= x+1
Therefore,
AE = CD+BC = 3x+3