Multiple Choice Question (MCQ)

In the figure, the area of rectangle CDEF is twice the area of rectangle ABCF . If CD=2x+2 , what is the length of AE , in terms of x ?

  1. ×

    2x=2

  2. ×

    2x+4

  3. ×

    3x+1

  4. ×

    3x+2

  5. 3x+3

Collected in the board: Rectangle

Steven Zheng posted 1 year ago

Answer

  1. Since the area of rectangle CDEF is twice the area of rectangle ABCF and the two triangles share sides in the same length,

    CD = 2BC

    BC = \dfrac{1}{2}CD

    =\dfrac{1}{2}(2x+2)

    = x+1

    Therefore,

    AE = CD+BC = 3x+3

Steven Zheng posted 1 year ago

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