In the figure, the area of rectangle $$ CDEF $$ is twice the area of rectangle $$ ABCF $$ . If $$ CD=2x+2 $$ , what is the length of $$ AE $$ , in terms of $$ x $$ ?

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Uniteasy Admin · Accepted Answer

Since the area of rectangle CDEF is twice the area of rectangle ABCF and the two triangles share sides in the same length,
$$CD = 2BC$$
$$BC = \dfrac{1}{2}CD$$
$$=\dfrac{1}{2}(2x+2)    $$
$$= x+1$$
Therefore,
$$AE = CD+BC = 3x+3$$

Multiple Choice Question (MCQ)

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