Question
Given a triangle △ABC with AC=15 , BC=7 and
∠ACB=60 , find the value of AB .
Given a triangle △ABC with AC=15 , BC=7 and
∠ACB=60 , find the value of AB .
Using the Law of Cosines
c^2=a^2+b^2-2ab\cos C
c^2 = 15^2+7^2-2\times 15\times 7\cos 60\degree
c^2 = 15^2+7^2- 15\times 7
=15\times 8+49
=169
\therefore c = 13