Selective Question
Answer
-
Factor the top and bottom and cancel the factors they have in common
\dfrac{6x^2-x-2}{4x^2-1}
=\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}
= \dfrac{3x-2}{2x-1}
Factor the top and bottom and cancel the factors they have in common
\dfrac{6x^2-x-2}{4x^2-1}
=\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}
= \dfrac{3x-2}{2x-1}