For all x ≠ \dfrac{1}{2} , \dfrac{6x^2-x-2}{4x^2-1}=
-
×
\dfrac{2-3x}{2x+1}
-
×
\dfrac{3x+2}{2x+1}
-
×
\dfrac{3x+2}{2x-1}
-
×
\dfrac{3x-2}{2x+1}
-
✓
\dfrac{3x-2}{2x-1}
Steven Zheng
posted 1 month ago
Selective Question
Answer
-
Factor the top and bottom and cancel the factors they have in common
\dfrac{6x^2-x-2}{4x^2-1}
=\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}
= \dfrac{3x-2}{2x-1}
Steven Zheng
posted 1 month ago