For all x ≠ \dfrac{1}{2} , \dfrac{6x^2-x-2}{4x^2-1}=
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×
\dfrac{2-3x}{2x+1}
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×
\dfrac{3x+2}{2x+1}
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×
\dfrac{3x+2}{2x-1}
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×
\dfrac{3x-2}{2x+1}
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✓
\dfrac{3x-2}{2x-1}
Steven Zheng
posted 7 months ago
Selective Question
Answer
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Factor the top and bottom and cancel the factors they have in common
\dfrac{6x^2-x-2}{4x^2-1}
=\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}
= \dfrac{3x-2}{2x-1}
Steven Zheng
posted 7 months ago