Selective Question

For all x \dfrac{1}{2} , \dfrac{6x^2-x-2}{4x^2-1}=

  1. ×

    \dfrac{2-3x}{2x+1}

  2. ×

    \dfrac{3x+2}{2x+1}

  3. ×

    \dfrac{3x+2}{2x-1}

  4. ×

    \dfrac{3x-2}{2x+1}

  5. \dfrac{3x-2}{2x-1}

Steven Zheng Steven Zheng posted 1 week ago


Answer

  1. Factor the top and bottom and cancel the factors they have in common

    \dfrac{6x^2-x-2}{4x^2-1}

    =\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}

    = \dfrac{3x-2}{2x-1}

Steven Zheng Steven Zheng posted 1 week ago

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