For all $$ x $$ ≠ $$ \dfrac{1}{2} $$ , $$ \dfrac{6x^2-x-2}{4x^2-1}= $$

Question

For all $$ x $$ ≠ $$  \dfrac{1}{2} $$ ,  $$ \dfrac{6x^2-x-2}{4x^2-1}=  $$

Uniteasy Admin · Accepted Answer

Factor the top and bottom and cancel the factors they have in common

$$ \dfrac{6x^2-x-2}{4x^2-1}  $$ 
$$ =\dfrac{(3x-2)(2x+1)}{(2x+1)(2x-1)}  $$
$$ = \dfrac{3x-2}{2x-1}  $$

Multiple Choice Question (MCQ)

Answer