If $$ 2x+y=0 $$ , which one is correct for the value of the fractional expression
$$ \dfrac{x^2+xy+y^2}{2xy-x^2} $$

Question

If $$ 2x+y=0 $$ , which one is correct for the value of the fractional expression 
$$ \dfrac{x^2+xy+y^2}{2xy-x^2} $$

Uniteasy Admin · Accepted Answer

$$\because 2x+y = 0 $$
$$y = -2x$$
Substituting to the equation yields
$$ \dfrac{x^2+xy+y^2}{2xy-x^2} $$
$$= \dfrac{x^2-2x^2+4x^2}{2x(-2x)-x^2}  $$
$$= -\dfrac{3}{5}  $$

Multiple Choice Question (MCQ)

Answer