Multiple Choice Question (MCQ)

If 2x+y=0 , which one is correct for the value of the fractional expression

\dfrac{x^2+xy+y^2}{2xy-x^2}

  1. ×

    -\dfrac{1}{5}

  2. -\dfrac{3}{5}

  3. ×

    1

  4. ×

    Undefined

Collected in the board: Fractions

Steven Zheng posted 11 months ago


Answer

  1. \because 2x+y = 0

    y = -2x

    Substituting to the equation yields

    \dfrac{x^2+xy+y^2}{2xy-x^2}

    = \dfrac{x^2-2x^2+4x^2}{2x(-2x)-x^2}

    = -\dfrac{3}{5}

Steven Zheng posted 1 month ago

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