If $$ x=2 $$ , $$ y=-\dfrac{1}{2} $$ , find the value of $$ 4x^2y-[6xy-3(4xy-2)-x^2y]+1 $$

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If $$ x=2 $$ , $$ y=-\dfrac{1}{2} $$  , find the value of $$ 4x^2y-[6xy-3(4xy-2)-x^2y]+1 $$

Uniteasy Admin · Accepted Answer

Simplify the integral expression, combine the like terms
$$ 4x^2y-[6xy-3(4xy-2)-x^2y]+1 $$
$$ =3x^2y+6xy-5 $$
And then plug in the value of $$ x $$ , $$ y $$ , we have,
$$ 3×2^2×(-\dfrac{1}{2}) +6×2×(-\dfrac{1}{2} )-5 $$
$$ =-6-6-5=-17 $$

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