#### Question

If x=2 , y=-\dfrac{1}{2} , find the value of 4x^2y-[6xy-3(4xy-2)-x^2y]+1

Steven Zheng posted 1 month ago

Simplify the integral expression, combine the like terms

4x^2y-[6xy-3(4xy-2)-x^2y]+1

=3x^2y+6xy-5

And then plug in the value of x , y , we have,

3×2^2×(-\dfrac{1}{2}) +6×2×(-\dfrac{1}{2} )-5

=-6-6-5=-17

Steven Zheng posted 1 month ago

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