Question Given a+b=8 , ab=2 , find value of (a-b)^2 Collected in the board: Perfect square polynomials Steven Zheng posted 3 years ago
Answer Given a+b=8Square both sides of the equation a^2+2ab+b^2=64Plug in ab=2a^2+b^2=64-2\cdotp 2 =60(a-b)^2=a^2-2ab+b^2=60-2\cdotp 2 =56 Steven Zheng posted 2 years ago