#### Question

Determine the value of \dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1}

Question

Determine the value of \dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1}

Reverse Difference of Squares on the product term of the denominator,

The expression is simplified

\dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1}

=\dfrac{2007²}{2007²-1+1}

=1

So the value of the expression is 1