Question
Determine the value of \dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1}
Answer
Reverse Difference of Squares on the product term of the denominator,
The expression is simplified
\dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1}
=\dfrac{2007²}{2007²-1+1}
=1
So the value of the expression is 1