Determine the value of $$ \dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1} $$

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Determine the value of $$ \dfrac{  2007²}{(2007＋1)×(2007－1) ＋1} $$

Uniteasy Admin · Accepted Answer

Reverse Difference of Squares on the product term of the denominator,
The expression is simplified 
$$ \dfrac{ 2007²}{(2007＋1)×(2007－1) ＋1} $$
$$=\dfrac{2007²}{2007²-1+1} $$
$$=1$$
So the value of the expression is 1

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