Question
Answer
(a+b+c)^3-a^3-b^3-c^3
=(b+c) [(a+b+c)^2-(a+b+c)a+a^2]-(b +c)(b^2-bc+c^2)
Steven Zheng
posted 3 months ago
(a+b+c)^3-a^3-b^3-c^3
=(b+c) [(a+b+c)^2-(a+b+c)a+a^2]-(b +c)(b^2-bc+c^2)
Steven Zheng
posted 3 months ago