Question
(x-1)(x-2)(x-3)(x-4)-48
Answer
(x-1)(x-2)(x-3)(x-4)-48
=[(x^2-5x)+4][(x^2-5x)+6]-48
t=x^2-5x
t^2+10t+24-48
t^2+10t-24
(t+12)(t-2)
(x^2-5x+12)(x^2-5x-2)
(x-1)(x-2)(x-3)(x-4)-48
(x-1)(x-2)(x-3)(x-4)-48
=[(x^2-5x)+4][(x^2-5x)+6]-48
t=x^2-5x
t^2+10t+24-48
t^2+10t-24
(t+12)(t-2)
(x^2-5x+12)(x^2-5x-2)