Question

If \dfrac{1}{x}-\dfrac{1}{y}=3 , find the value of \dfrac{2x+3xy-2y}{x-2xy-y}

Collected in the board: Fractions

Steven Zheng posted 1 year ago


Answer

\dfrac{1}{x}-\dfrac{1}{y}=3

x-y = -3xy

\dfrac{2x+3xy-2y}{x-2xy-y}

=\dfrac{-6xy+3xy}{-5xy}

=\dfrac{3}{5}

Steven Zheng posted 1 year ago

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