Question
If \dfrac{1}{x}-\dfrac{1}{y}=3 , find the value of \dfrac{2x+3xy-2y}{x-2xy-y}
If \dfrac{1}{x}-\dfrac{1}{y}=3 , find the value of \dfrac{2x+3xy-2y}{x-2xy-y}
\dfrac{1}{x}-\dfrac{1}{y}=3
x-y = -3xy
\dfrac{2x+3xy-2y}{x-2xy-y}
=\dfrac{-6xy+3xy}{-5xy}
=\dfrac{3}{5}