Question


Answer

(x-\dfrac{2x}{x-1})÷\dfrac{x^2-2x+1}{x^2-1}

=\dfrac{x(x-1)-2x}{x-1} ÷\dfrac{(x-1)^2}{x^2-1}

=\dfrac{x^2-3x}{x-1} \cdotp (x-1)

=x^2-3x

Steven Zheng posted 2 weeks ago

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