If a=\dfrac{xbc}{1x} , what is the value of x in terms of a, b and c?

×
\dfrac{abc}{a1}

×
\dfrac{bac}{a1}

✓
\dfrac{a+bc}{a+1}

×
\dfrac{ac+b}{a+1}
If a=\dfrac{xbc}{1x} , what is the value of x in terms of a, b and c?
\dfrac{abc}{a1}
\dfrac{bac}{a1}
\dfrac{a+bc}{a+1}
\dfrac{ac+b}{a+1}
Given the expression
a=\dfrac{xbc}{1x}
Multiply both sides of the equation by 1x to remove the denominator
aax=xbc
Rearrange the terms and factor out x
(a+1)x=a+bc
Divide both sides by a+1, and then,
x= \dfrac{a+bc}{a+1}
C is correct choice