Question


Answer

\because x-y=2
(1)

Squaring both sides,

(x-y)^2 = 4

\therefore x^2+y^2-2xy = 4

\because x^2+y^2=4

xy=0

x=0 or y=0

if x=0, y=-2

if y=0,x=2

Either cases yields the same result,

x^{2002}+y^{2002}

= 2^{2002}

Steven Zheng posted 2 months ago

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