#### Question

#### Answer

(1) In △PCD , make parallel line to CD through point E .

\because AB⊥ plane PBC , AB \parallel CD

\therefore EF ⊥ plane PBC , EF⊥BF

\because E is the midpoint of PD

\therefore EF = \dfrac{1}{2} DC = AB

\therefore ABFE is a rectangle

AE \parallel plane PBC

(2) \because E is the midpoint of PD, EF \parallel CD

F is also the midpoint of PC

\because △PBC is right triangle,

BF ⊥ PC

\because BF⊥ plane PDC

AE⊥ plane PDC