Given quadrilateral $$ ABCD $$ , $$ BC BA $$ , $$ AD = DC $$ , $$ BD $$ bisects $$ ∠BAC $$ . Prove $$ ∠BAD + ∠C = 180° $$

Question

Given quadrilateral $$ ABCD $$ ,  $$ BC > BA $$ ,  $$ AD = DC $$ ,  $$ BD $$ bisects $$ ∠BAC $$ . Prove $$ ∠BAD + ∠C = 180° $$