Question


Answer

(a^2+b^2-c^2)^2-4a^2b^2

=(a^2+b^2-c^2+2ab)(a^2+b^2-c^2-2ab)

=\big[ (a+b)^2-c^2\big] \big[ (a-b)^2-c^2\big]

=(a+b+c)(a+b-c)(a-b+c)(a-b-c)

Steven Zheng posted 1 year ago

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