Connect DF, EG, interesting at point GQ. Apparently, Q is the midpoint of DF and EG.

Connect OQ. So we get,

A_{ODQ}=A_{OFQ} in \triangle ODF,

A_{OEQ}=A_{OGQ} in \triangle OEG

Let T be the area of the square ABCD


=(\dfrac{1}{4}T+A_{OGQ}+A_{OFQ}) + (\dfrac{1}{4}T-A_{ODQ}-A_{OFQ})





A_{ODAG}+A_{OECF} = \dfrac{1}{2}T

A_{OECF} = \dfrac{1}{2}T - A_{ODAG}



Therefore, the area of the shaded region is 35 cm^2

Steven Zheng posted 2 years ago

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