Multiple Choice Question (MCQ)
If \sqrt{x} = \sqrt{a}+\sqrt{b}, then which of the following is equivalent
to x ?

✓
a + b + 2\sqrt{ab}

×
a + b + 2ab

×
a + b + ab

×
a + b

×
2a + 2b
If \sqrt{x} = \sqrt{a}+\sqrt{b}, then which of the following is equivalent
to x ?
a + b + 2\sqrt{ab}
a + b + 2ab
a + b + ab
a + b
2a + 2b
If \sqrt{x} = \sqrt{a}+\sqrt{b}, then taking square on both sides will give the value of x
x = ( \sqrt{a}+\sqrt{b})^2
=(\sqrt{a} )^2+(\sqrt{b} )^2+2\sqrt{a}\sqrt{b}
=a+b+2\sqrt{ab}
Therefore, A is the correct choice