Let m and n be the two roots of the equation $$x^2 − 15x + 28 = 0$$. Find the value of $$ (m + 1)(n + 1)$$

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Uniteasy Admin · Accepted Answer

Expand brackets of $$(m + 1)(n + 1)$$
$$ (m + 1)(n + 1)$$
$$=mn+m+n+1$$
Since m and n be the two roots of the equation $$x^2 − 15x + 28 = 0$$, the following equations are established by using Vieta's formula
$$m+n = 15$$ and $$mn=28$$
Therefore,
$$ (m + 1)(n + 1)$$
$$= 15+28+1$$
$$=44$$

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