Rationalizing the denominator of $$\dfrac{1}{\sqrt{7}-\sqrt{6} }$$ gives

Question

Rationalizing the denominator of $$\dfrac{1}{\sqrt{7}-\sqrt{6}    }$$  gives

Uniteasy Admin · Accepted Answer

Multiply both nominator and denominator with $$\sqrt{7}+\sqrt{6} $$ to rationalize the denominator 
$$\dfrac{1}{\sqrt{7}-\sqrt{6}    }$$
$$=\dfrac{1}{\sqrt{7}-\sqrt{6}}\cdot \dfrac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}}   $$
$$=\dfrac{\sqrt{7}+\sqrt{6}}{(\sqrt{7}  )^2-(\sqrt{6}  )^2} $$ 
$$=\dfrac{\sqrt{7}+\sqrt{6}}{7-6}  $$
$$=\sqrt{7}+\sqrt{6}$$
Therefore, C is right choice

Multiple Choice Question (MCQ)

Answer