Multiple Choice Question (MCQ)
If a^2-3a + 1 = 0, (a\ne 0 ), then the value of a^2 + \dfrac{1}{a^2} is
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×
4
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✓
7
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×
8
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×
13
If a^2-3a + 1 = 0, (a\ne 0 ), then the value of a^2 + \dfrac{1}{a^2} is
4
7
8
13
a^2-3a + 1 = 0
Divide both sides by a, then
a + \dfrac{1}{a} =3
Square both sides
a^2 + \dfrac{1}{a^2} +2 = 9
Then
a^2 + \dfrac{1}{a^2} = 7
Therefore
B is the right choice