Multiple Choice Question (MCQ)

Find a Pythagorean triplet in which one member is 12.

  1. ×

    7,12,19

  2. 5,12,13

  3. ×

    11,12,15

  4. ×

    11,12,18

Collected in the board: Square of numbers

Steven Zheng posted 1 hour ago

Answer

  1. 7,12,19

    19^2-12^2 = (19-12)(19+12) = 7\cdot 31=217 \ne7^2

    Therefore,

    7,12,19 does not constitute a Pythagorean triplet

  2. 5,12,13

    13^2-12^2 = (13-12)(13+12) = 25 = 5^2

    Therefore,

    5,12,13 forms a Pythagorean triplet

  3. 11,12,15

    15^2-12^2 = (15-12)(15+12) = 3\cdot 25 = 75\ne 11^2

    11,12,15 does not constitute a Pythagorean triplet

  4. 11,12,18

    18^2-12^2=(18-12)(18+12) = 6\cdot30 = 180\ne11^2

    11,12,18 does not constitute a Pythagorean triplet

Steven Zheng posted 1 hour ago

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