Multiple Choice Question (MCQ)
Find a Pythagorean triplet in which one member is 12.
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×
7,12,19
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✓
5,12,13
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×
11,12,15
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×
11,12,18
Find a Pythagorean triplet in which one member is 12.
7,12,19
5,12,13
11,12,15
11,12,18
7,12,19
19^2-12^2 = (19-12)(19+12) = 7\cdot 31=217 \ne7^2
Therefore,
7,12,19 does not constitute a Pythagorean triplet
5,12,13
13^2-12^2 = (13-12)(13+12) = 25 = 5^2
Therefore,
5,12,13 forms a Pythagorean triplet
11,12,15
15^2-12^2 = (15-12)(15+12) = 3\cdot 25 = 75\ne 11^2
11,12,15 does not constitute a Pythagorean triplet
11,12,18
18^2-12^2=(18-12)(18+12) = 6\cdot30 = 180\ne11^2
11,12,18 does not constitute a Pythagorean triplet