Question
If a=-\dfrac{29}{37} , b=-\dfrac{45}{37} , find the value of a^3-6ab+b^3
If a=-\dfrac{29}{37} , b=-\dfrac{45}{37} , find the value of a^3-6ab+b^3
a+b
= -\dfrac{29}{37}-\dfrac{45}{37}
= -2
a^3-6ab+b^3
= (a+b)(a^2-ab+b^2)-6ab
=-2a^2+2ab-2b^2-6ab
=-2(a+b)^2
=-8