Answer

xyz+xy+xz+yz+x+y+z+1

=xy(z+1) + (z+1)+ z(x+y)+(x+y)

=(z+1)(xy+1)+(z+1)(x+y)

=(z+1)(xy+x+y+1)

=(z+1)(x+1)(y+1)

Steven Zheng posted 21 hours ago

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