$$x = \sqrt{11-2yz}, y=\sqrt{12-2xz},z = \sqrt{13-2xy} $$
The value of $$x+y+z$$ is

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Uniteasy Admin · Accepted Answer

$$x = \sqrt{11-2yz}, y=\sqrt{12-2xz},z = \sqrt{13-2xy} $$
Square both sides of the equations and addition of them yields
$$x^2+y^2+z^2 = 11+12+13-2(yz+xZ+xy)$$
Then
$$(x+y+z)^2 = 36 $$
$$x+y+z = 6$$
THerefore,
B is the correct option.

Multiple Choice Question (MCQ)

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