Question
Find the value of \sin(-600\degree)
Find the value of \sin(-600\degree)
\sin(-600\degree)
= - \sin 600\degree
= - \sin (360\degree +240\degree)
=-\sin240\degree
=- \sin (180\degree +60\degree)
=\sin60\degree = \dfrac{\sqrt{3} }{2}
Therefore,
The value of \sin(-600\degree) is \dfrac{\sqrt{3} }{2}