What is the solution $$(x,y)$$ to the system of equations below?
$$ \begin{alignedat}{2} 3 &x+ &4 &y = -23 \ 2 & y- & &x = -19 \end{alignedat}$$

Question

What is the solution $$(x,y)$$ to the system of equations below?
$$ \begin{alignedat}{2} 3 &x+  &4 &y = -23 \  2 & y- &  &x = -19 \end{alignedat}$$

Uniteasy Admin · Accepted Answer

$$ \begin{alignedat}{2} 3 &x+  &4 &y = -23 \  2 & y- &  &x = -19 \end{alignedat}$$
Multiplying both sides of 2nd equation by 3 gives

$$ \begin{alignedat}{2} 3 &x+  &4 &y = -23 \  6 & y- &  3&x = -57 \end{alignedat}$$
Addition of the two equations to cancel term with $$x$$
$$10y = -80$$
$$y=-8$$
Back substitution yields
$$x = 3$$
B is correct choice

Multiple Choice Question (MCQ)

Answer