What is the solution (x,y) to the system of equations below?
\begin{alignedat}{2} 3 &x+ &4 &y = 23 \\ 2 & y & &x = 19 \end{alignedat}

×
(5,2)

✓
(3,8)

×
(3,6)

×
(9,6)
What is the solution (x,y) to the system of equations below?
\begin{alignedat}{2} 3 &x+ &4 &y = 23 \\ 2 & y & &x = 19 \end{alignedat}
(5,2)
(3,8)
(3,6)
(9,6)
\begin{alignedat}{2} 3 &x+ &4 &y = 23 \\ 2 & y & &x = 19 \end{alignedat}
Multiplying both sides of 2nd equation by 3 gives
\begin{alignedat}{2} 3 &x+ &4 &y = 23 \\ 6 & y & 3&x = 57 \end{alignedat}
Addition of the two equations to cancel term with x
10y = 80
y=8
Back substitution yields
x = 3
B is correct choice