The sum of the zeros of y = 3x^2  6x  4 is

×
2

×
\dfrac{4}{3}

×
\dfrac{4}{3}

✓
2

×
6
The sum of the zeros of y = 3x^2  6x  4 is
2
\dfrac{4}{3}
\dfrac{4}{3}
2
6
The sum of zeros, that is, the sum of two roots of a quadratic equation ax^2=bx+c=0 is equal to \dfrac{b}{a}
Therefore, for quadratic function y=3x^26x4
\dfrac{b}{a}=\dfrac{6}{3} =2
The correct answer is D