Multiple Choice Question (MCQ)
The sum of the zeros of y = 3x^2 - 6x - 4 is
-
×
-2
-
×
-\dfrac{4}{3}
-
×
\dfrac{4}{3}
-
✓
2
-
×
6
The sum of the zeros of y = 3x^2 - 6x - 4 is
-2
-\dfrac{4}{3}
\dfrac{4}{3}
2
6
The sum of zeros, that is, the sum of two roots of a quadratic equation ax^2=bx+c=0 is equal to -\dfrac{b}{a}
Therefore, for quadratic function y=3x^2-6x-4
-\dfrac{b}{a}=-\dfrac{-6}{3} =2
The correct answer is D