Multiple Choice Question (MCQ)
Find the zeros of y = 2x^2 + x - 6.
-
×
3 and 2
-
×
-3 and 2
-
×
\dfrac{1}{2} and \dfrac{3}{2}
-
×
-\dfrac{3}{2} and 1
-
✓
\dfrac{3}{2} and -2
Find the zeros of y = 2x^2 + x - 6.
3 and 2
-3 and 2
\dfrac{1}{2} and \dfrac{3}{2}
-\dfrac{3}{2} and 1
\dfrac{3}{2} and -2
when the function has zeros, y=0
Then
2x^2+x-6=0
Factoring the quadratic expression
(2x-3)(x+2)=0
Therefore,
x= \dfrac{3}{2} or x= -2
The two zeros are \dfrac{3}{2} and -2