Multiple Choice Question (MCQ)

Find the zeros of y = 2x^2 + x - 6.

  1. ×

    3 and 2

  2. ×

    -3 and 2

  3. ×

    \dfrac{1}{2} and \dfrac{3}{2}

  4. ×

    -\dfrac{3}{2} and 1

  5. \dfrac{3}{2} and -2

Collected in the board: Quadratic function

Steven Zheng posted 2 weeks ago


Answer

  1. when the function has zeros, y=0

    Then

    2x^2+x-6=0

    Factoring the quadratic expression

    (2x-3)(x+2)=0

    Therefore,

    x= \dfrac{3}{2} or x= -2

    The two zeros are \dfrac{3}{2} and -2

Steven Zheng posted 2 weeks ago

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