Multiple Choice Question (MCQ)
The equation of the axis of symmetry of the function y = 2x^2 + 3x - 6 is
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×
x=-\dfrac{3}{2}
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✓
x=-\dfrac{3}{4}
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×
x=-\dfrac{1}{3}
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×
x=\dfrac{1}{3}
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×
x=\dfrac{3}{4}
The equation of the axis of symmetry of the function y = 2x^2 + 3x - 6 is
x=-\dfrac{3}{2}
x=-\dfrac{3}{4}
x=-\dfrac{1}{3}
x=\dfrac{1}{3}
x=\dfrac{3}{4}
For a quadratic function y =ax^2+bx+c
Its equation of the axis of symmetry is
x = -\dfrac{b}{2a}
For the function y=2x^2+3x−6 ,
a= 2, b= 3
Therefore, its equation of the axis of symmetry is
x=-\dfrac{3}{4}
The correct choice is B