The equation of the axis of symmetry of the function y = 2x^2 + 3x  6 is

×
x=\dfrac{3}{2}

✓
x=\dfrac{3}{4}

×
x=\dfrac{1}{3}

×
x=\dfrac{1}{3}

×
x=\dfrac{3}{4}
The equation of the axis of symmetry of the function y = 2x^2 + 3x  6 is
x=\dfrac{3}{2}
x=\dfrac{3}{4}
x=\dfrac{1}{3}
x=\dfrac{1}{3}
x=\dfrac{3}{4}
For a quadratic function y =ax^2+bx+c
Its equation of the axis of symmetry is
x = \dfrac{b}{2a}
For the function y=2x^2+3x−6 ,
a= 2, b= 3
Therefore, its equation of the axis of symmetry is
x=\dfrac{3}{4}
The correct choice is B