Multiple Choice Question (MCQ)
The coordinates of the vertex of the parabola whose equation is y = 2x^2 + 4x - 5 are
-
×
(2, 11)
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✓
(-1, -7)
-
×
(1, 1)
-
×
(-2, -5)
-
×
(-4, 11)
The coordinates of the vertex of the parabola whose equation is y = 2x^2 + 4x - 5 are
(2, 11)
(-1, -7)
(1, 1)
(-2, -5)
(-4, 11)
For a quadratic function y=ax^2+bx+c, the coordinates of its vertex is
(-\dfrac{b}{2a},\dfrac{4ac-b^2}{4a} )
Here for the function y=2x^2+4x-5, the coordinates of its vertex is
(-\dfrac{4}{2\times 2 } ,\dfrac{4\cdotp 2\cdotp (-5)-4^2 }{4\times 2 } )
That is
(-1, -7)
So the correction answer is B