The coordinates of the vertex of the parabola whose equation is y = 2x^2 + 4x  5 are

×
(2, 11)

✓
(1, 7)

×
(1, 1)

×
(2, 5)

×
(4, 11)
The coordinates of the vertex of the parabola whose equation is y = 2x^2 + 4x  5 are
(2, 11)
(1, 7)
(1, 1)
(2, 5)
(4, 11)
For a quadratic function y=ax^2+bx+c, the coordinates of its vertex is
(\dfrac{b}{2a},\dfrac{4acb^2}{4a} )
Here for the function y=2x^2+4x5, the coordinates of its vertex is
(\dfrac{4}{2\times 2 } ,\dfrac{4\cdotp 2\cdotp (5)4^2 }{4\times 2 } )
That is
(1, 7)
So the correction answer is B