Multiple Choice Question (MCQ)

The coordinates of the vertex of the parabola whose equation is y = 2x^2 + 4x - 5 are

  1. ×

    (2, 11)

  2. (-1, -7)

  3. ×

    (1, 1)

  4. ×

    (-2, -5)

  5. ×

    (-4, 11)

Collected in the board: Quadratic function

Steven Zheng posted 3 weeks ago


Answer

  1. For a quadratic function y=ax^2+bx+c, the coordinates of its vertex is

    (-\dfrac{b}{2a},\dfrac{4ac-b^2}{4a} )

    Here for the function y=2x^2+4x-5, the coordinates of its vertex is

    (-\dfrac{4}{2\times 2 } ,\dfrac{4\cdotp 2\cdotp (-5)-4^2 }{4\times 2 } )

    That is

    (-1, -7)

    So the correction answer is B

Steven Zheng posted 3 weeks ago

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