Question

Simplify the square root expression

\dfrac{\sqrt{2}+\sqrt{6} }{1+\sqrt{3} }

Collected in the board: Square Root

Steven Zheng posted 3 weeks ago


Answer

\dfrac{\sqrt{2}+\sqrt{6} }{1+\sqrt{3} }

=\sqrt{ \Big( \dfrac{\sqrt{2}+\sqrt{6} }{1+\sqrt{3} }\Big)^2}

=\sqrt{\dfrac{8+4\sqrt{3} }{4+2\sqrt{3} } }=2

Steven Zheng posted 3 weeks ago

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