Multiple Choice Question (MCQ)

\sin^{-1}\sin \dfrac{2\pi}{3}=

  1. ×

    \dfrac{2\pi}{3}

  2. ×

    \dfrac{\pi}{6}

  3. ×

    \dfrac{3\pi}{4}

  4. \dfrac{\pi}{3}

Collected in the board: Inverse function

Steven Zheng posted 1 month ago


Answer

  1. \sin \dfrac{2\pi}{3} =\dfrac{\sqrt{3} }{2}

    \arcsin \dfrac{\sqrt{3} }{2} =\dfrac{\pi}{3}

    \therefore \sin^{-1}\sin \dfrac{2\pi}{3}= \dfrac{\pi}{3}

Steven Zheng posted 1 month ago

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