Multiple Choice Question (MCQ)
\sin^{-1}\sin \dfrac{2\pi}{3}=
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×
\dfrac{2\pi}{3}
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×
\dfrac{\pi}{6}
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×
\dfrac{3\pi}{4}
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✓
\dfrac{\pi}{3}
Answer
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\sin \dfrac{2\pi}{3} =\dfrac{\sqrt{3} }{2}
\arcsin \dfrac{\sqrt{3} }{2} =\dfrac{\pi}{3}
\therefore \sin^{-1}\sin \dfrac{2\pi}{3}= \dfrac{\pi}{3}