In the given figure, if \angle BAC = 25°, the value of \angle BOC is

×
135\degree

×
145\degree

✓
155\degree

×
165\degree
In the given figure, if \angle BAC = 25°, the value of \angle BOC is
135\degree
145\degree
155\degree
165\degree
AB and AC are the tangent to the circle. So,
AB\perp OB and AC\perp OC
In the quadrilateral ABOC,
\angle BAC+\angle ACO+\angle BOC+\angle OBA=360\degree
25\degree +90\degree + \angle BOC+90\degree =360\degree
\therefore \angle BOC =155\degree