Question


Answer

Let m^2=x^2+13x+3

4m^2=4x^2+4\times 13x+13^2-13^2+12

(2x+13)^2-(2m)^2+169-12=157)

(2x+13-2m)(2x+13+2m) =157

Let a=2x+13-2m, b=2x+13+2m

\therefore x=\dfrac{a+b-26}{4}

And

a\cdotp b=157=1\times157

Therefore

a=1,b=157

x=33

m^2 = 33^2+13\times 33+3 = 1521

m = 39

Steven Zheng posted 1 month ago

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