Question

If \theta \in [0,2\pi], find the maximum value of

f = |\sin^2 \theta {\sin^3(2\theta )\cdotp \sin^3 (4\theta ) \dots\sin^3 (2^{n-1} }\sin (2^n\theta )|

Collected in the board: Trigonometry

Steven Zheng posted 1 month ago


Answer

Steven Zheng Steven Zheng posted the answer 1 month ago

This answer is set private or in draft.

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