Question

Express \dfrac{\sqrt{3} }{2}\sin x+\dfrac{1}{2}\cos x in terms of sum of angles for sines function.

Collected in the board: Trigonometry

Steven Zheng posted 2 months ago


Answer

\dfrac{\sqrt{3} }{2}\sin x+\dfrac{1}{2}\cos x

= \cos \dfrac{\pi}{6} \sin x+ \sin \dfrac{\pi}{6}\cos x

=\sin (x+\dfrac{\pi}{6})

Steven Zheng posted 2 months ago

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