Question

Determine the value of \dfrac{1+\tan 15\degree }{1-\tan 15\degree }

Collected in the board: Trigonometry

Steven Zheng posted 2 months ago


Answer

\because \tan 45\degree =1

\therefore \dfrac{1+\tan 15\degree }{1-\tan 15\degree } = \dfrac{\tan 45\degree +\tan 15\degree }{\tan 45\degree -\tan 15\degree }

=\tan (45\degree +15\degree )

=\tan 60\degree

=\sqrt{3}

Steven Zheng posted 2 months ago

Scroll to Top