Question

If \tan \theta =\sqrt{\dfrac{1-a}{a} } \, (0 < a <1), simplify the expression:


\dfrac{\sin^2 \theta }{a+\cos \theta }+\dfrac{\sin^2 \theta }{a-\cos \theta }

Collected in the board: Trigonometry

Steven Zheng Steven Zheng posted 1 week ago

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